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Absolute Value Inequalities
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Investigating Liner Equations Using Graphing Calculator
Graphically solving a System of two Linear Equatio
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Graphs of Rational Functions
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Graphing Systems of Linear Equat
Solving Inequalities with Absolute Values
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Inequalities and Applications
Using MATLAB to Solve Linear Inequalities
Equations and Inequalities
Graph Linear Inequalities in Two Variables
Solving Equations & Inequalities
Teaching Inequalities:A Hypothetical Classroom Case
Graphing Linear Inequalities and Systems of Inequalities
Inequalities and Applications
Solving Inequalities
Quadratic Inequalities
Solving Systems of Linear Equations by Graphing
Systems of Equations and Inequalities
Graphing Linear Inequalities
Solving Inequalities
Solving Inequalities
Solving Equations Algebraically and Graphically
Graphing Linear Equations
Solving Linear Equations and Inequalities Practice Problems
Graphing Linear Inequalities
Equations and Inequalities
Solving Inequalities

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Graphically solving a System of two Linear Equatio

We will use the fact that the solution
to a system of equations of two variables and
two equations occurs at the point the graph of
the two equations intersect.

Remember that every point (x,y) on
the graph of an equations represents a
ordered x,y pair that is a solution to that
equation. The solution to a system of
equations is the ordered x,y pair that satisfies
both equations. The solution point must lie
on both graphs and the point of intersection is
the only point that does that.
We will now show how to find the
point of intersection. Let us solve the
following system:
First wemust solvethese equations for y because
we can only enter a y = equation in the calculator
3y=14-4x divideboth sides by 3
divideboth sides by -2

We could take more steps to put the
equations above in slope intercept form if we
were graphing them by hand. However that is
not necessary with the calculator.

We will now enter these two equations into the
calculator . Press “y=” to get to the equation screen. Press “clear” to clear any equations already in the calculator.


The key presses to in enter the two equations into the calculator are shown above. Notice we use the key for x shown by the second from the top arrow on the picture to our left. And we use the parenthesis shown by the third arrow to insure the 14 and -4x are both divided by 3 in the first equation. Finally we use negative key shown by the bottom arrow for the negative 2 divisor in the second equation. We used the on the right side of the calculator when we wanted to subtract as in 14-4x. But if there is nothing to subtract from and we wish to denote a negative number or the negative of a variable we must use . Study how these two keys are used and make sure you understand when to use each.
Finally press graph (top arrow) to graph the two equations.

We see the two equations do intersect as shown by the circle. We must find the intersection.


Our key presses so far are shown below.

We press then to get to the screen at our left. We need to find the coordinates of the intersection so we press 5 for intersection from the menu.

The calculator is asking us which curves we want it to find the intersection of. If we have cleared all the old equations in the first step there should only be 2 graphs and so the cursor should be on the first curve and all we have to do is press enter to confirm that this one of the curves we want to intersect. Press enter at this time.


Notice the cursor jumped to the next curve and the calculator is asking us to confirm that this is the other curve we want it to find the intersection of. Press enter to confirm. So far we have pressed the keys below.


The calculator is now asking for a guess . You could move the cursor closer to the intersection using the right arrow (up and down arrows jump you to other curves, only left and right arrows move you along curves). The present location of the cursor is close enough for our purposes. Press enter (the third time in a row) to accept this guess. The complete list of key presses to solve this system is shown below.

We now have a solution x=2 and y=2. That is the coordinates of the point of intersection.